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Help needed with date

 
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Top Forums UNIX for Dummies Questions & Answers Help needed with date
# 1  
Old 03-30-2008
Help needed with date
How can i assign a variable by the name of CUTDATE= today date - 90 days? i have something like this right now :-

Code:
today=`date '+%Y%m%d'`
#cutdate = this is where i am having problem. i need today - 90 days

How can i accomplish this? After that i need to do delete the data which are more than 90 days old from a file xyz.log. My first problem is that variable cutdate. Any help will be really appreciated.

Thanks
# 2  
Old 03-30-2008
This is a very frequent topic here. Does your date command support the syntax date -d "90 days ago"?
# 3  
Old 03-30-2008
we are using Sun Solaris. So yes we do support -d. I tried searching on the forum but was not able to find one.
# 4  
Old 03-31-2008
My other problem is that every year month is different. Meaning in 2009 April might have 30 days. How can we accomplish this?.
# 5  
Old 03-31-2008
April has 30 days every year. The only tricky one is February. Anyway, if you don't want 90 days but 3 months ago, say that instead. Your date manual page will have plenty examples.
# 6  
Old 03-31-2008
Months ago is not working era. That is why i am trying something like :-

cutdate=`today-90`

but this one will give me the output wrong. Any help?
# 7  
Old 03-31-2008
The "months ago" syntax is only available through the GNU version of date..much to my chagrin on my 2.8 Solaris box; boy it'd be swell if they'd let me install it. You'll want to try something of a perl one-liner... I'd listed one not too long ago..but don't have the link handy.
 
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