[bash]Stripping lines from a list


 
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# 8  
Old 04-03-2008
I think i have figured it out...
Code:
nl list1.txt | awk '{print "no."$1  $2}' | sed -n '/no.2/p' | sed "s/no.2//g"

in this case, in the sed parts, the "no.2" would be $file =)
# 9  
Old 04-04-2008
The ^ in the original sed script takes care of anchoring the substitution to the start of the line.

I guess what I should have used was sed -n 's/^ [1-9][0-9]* //gp' (where probably the last character before the double slash should be a tab, depending somewhat on your nl -- to type a literal tab, in many shells, you need to escape it like ctrl-v tab.)
 
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