grep on file of small size


 
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# 1  
Old 03-06-2008
grep on file of small size

Hi everybody,
I would like to carry out a grep on files below a certain size.
First I thought to find the files with "find" and then pipe the result to grep.

e.g.
Code:
find /my_dir  -size -20  -print | grep hello

but in this way grep searches only the string hello in the file names.

Is there a way to pass to grep the file names found with "find"?

Thank you,
Fred

Last edited by Yogesh Sawant; 02-26-2010 at 02:45 PM.. Reason: added code tags
# 2  
Old 03-06-2008
Code:
find /my_dir -size -20 | xargs grep hello

also consider including this option in your find command: -type f
# 3  
Old 03-06-2008
Thank you it worked!
# 4  
Old 03-06-2008
I have some files names which are not unix standard so grep crashes and it seems to stop after a certain number of errors.

Is there a way to ignore errors? I tried the options -s but it didn't work.
# 5  
Old 03-06-2008
Try this:
Code:
find /my_dir -size -20 -type f -exec grep hello "{}"\;

Find doesn't quite after a certain number of errors but this should prevent odd filenames from giving so much trouble.
# 6  
Old 03-07-2008
I get the following error:
Code:
find: missing argument to `-exec'


Last edited by Yogesh Sawant; 02-26-2010 at 02:45 PM.. Reason: added code tags
# 7  
Old 03-07-2008
put a space between "{}" and \;
 
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