how to use cut to get the last field of a string?

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how to use cut to get the last field of a string?

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02-24-2008

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how to use cut to get the last field of a string?

If I am not sure of how many fields a string has, say
STR=/homt/root/dir1/dir2/../dirn
how to use "cut -d/ -f" to get dirn ?

meili100

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02-24-2008

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Using bash/ksh

Code:

echo ${STR##*/}

Cheers,
ZB

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Thanks, but what does ## mean here?

Quote:

Originally Posted by zazzybob

Using bash/ksh

Code:

echo ${STR##*/}

Cheers,
ZB

Last edited by meili100; 02-24-2008 at 03:39 PM..

meili100

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02-24-2008

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From man bash

Quote:

${parameter##word}
The word is expanded to produce a pattern just as in pathname
expansion. If the pattern matches the beginning of the value of
parameter, then the result of the expansion is the expanded
value of parameter with the shortest matching pattern (the ``#''
case) or the longest matching pattern (the ``##'' case) deleted.

So, I am deleting the longest pattern that matches "*/" - i.e. everything upto and including the last slash.

Cheers,
ZB

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