UNIX for Dummies Questions & Answers

I have the files logged in the file system with names in the format of : filename_ordernumber_date_time
eg:

file_1_12012007_1101.txt
file_2_12022007_1101.txt
file_1_12032007_1101.txt

I need to find out all the files that are logged multiple times with same order number. In the above eg, I need to get a

report like:

file_1: Submitted two times at 12012007_1101 , 12032007_1101

Code:

ls *.txt |
awk -F"_" '{
  split($4, a, ".")
  num[$2]++
  ord[$2]=$3"_"a[1]
} END {
  for (i in ord)
    if (num[i] > 1)
      print "file_"i": Submitted "num[i]" times "ord[i]
}'