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Using SED to get n chars after given value from file


 
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# 1  
Old 12-17-2007
Using SED to get n chars after given value from file

Hello, my name is Marc, I'm a linux starter Smilie and I hope you specialists can help me solving this issue.

I have a file containing a lot of data. Somewhere in this file, there's a string called "Faultdump", directly followed by 64 chars of HEX data. I need to get the HEX part. I accomplished this with several lines of code in a script calling sed, cut as well as head/tail. I know some of you guys will manage to get this on one line by using just awk or sed by avoiding cat or head/tail. Please can anyone of you point me to the right direction?

I was searching through the forums, but I'm afraid, I couldn't find an appropriate example.

Many thanks in advance!

Marc (Kally).
# 2  
Old 12-17-2007
sed -n 's/.*Faultdump\(.*\)/\1/p' filename| cut -c1-64

Should work.

Sure someone will improve on that though.

HTH
# 3  
Old 12-17-2007
Thanks Tytalus, I'll try it later. Looks a lot better than my commandlines.

If someone else has got another approach (using sed or awk completely alone), I'll appreciate that.

Anyway, I'm fine with Tytalus' solution, though.

Many thanks.
# 4  
Old 12-18-2007
I'm afraid, I tried it and it doesn't work properly, does anyone got another approach, may using AWK? I'm stuck. Smilie

Thank you very much.
# 5  
Old 12-18-2007
Try this one

awk '{ if(substr($0,65,9)=="Faultdump") print substr($0,1,64)}' filename
# 6  
Old 12-18-2007
@ranjithpr:

Thank you! I'll give you a report later then. Desi Greetings. Smilie

Marc.
# 7  
Old 12-18-2007
think that that awk will only work if the string faultdump starts at char 65.

so...

you could try :

grep Faultump <filename> | sed 's/.*Faultdump//' | cut -c1-64

What errors are you seeing when you try the earlier sed I gave ?
 

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