UNIX for Dummies Questions & Answers

@Tytalus:

There's some sort of other string before the HEX-Part:

THE_OTHER_STRING00AFFAE1...

Thanks for your patience!

P.s.: The content of my file is in *one* line.

ok - so you should be able to just change the cut params, e.g if the_other_string is say 12 chars long then use cut-c13-76

or is it some other error you are seeing ?

@Tytalus: I modified the cut string as you suggested and it works. Many thanks!

Now I understand better how sed works.

sed -n 's/^.*Faultdump\(.\{64\}\).*$/\1/p'

This doesn't print anything ("-n") save for lines explicitly marked for printing (the "p" at the end, which prints the line after changing it). For every line containing the word we searched for we do the following:
It is matched up to that word ("^.*Faultdump"), the following 64 characters are captured in a variable ( "\(.\{64\}\)" ), than the rest of the line is matched (".*$"). The whole matched line is then replaced by the part captured in the variable ("/\1/") and printed, as stated above.

I hope this helps.

bakunin

awk '/Faultdump/ { print substr($0,1,65) }' filename

That will print out the first 64 characters of the line containing "faultdump" instead of the 64 characters following the search item.

bakunin