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date in awk

 
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# 1  
Old 08-06-2007
date in awk
Hi,

Can anyone tell me how can we assign a system date to a variable in awk script? Also how can we use this varible to print this in an other file.

Regards,
Jamuna
# 2  
Old 08-06-2007
Code:
v=`date`
echo 1 | awk -v var=$v '{ print var }'

# 3  
Old 08-06-2007
one more without using intermediate variables
Smilie
Code:
awk 'BEGIN{ "date" | getline; print }'

# 4  
Old 08-06-2007
I have a file two files
rrp1
{optimal@Simha}110:cat rrp1
VALUE|DATE|USER|
123|||
243|||
432|||

rrp2
VALUE|USER|
243|RRP|

below scipt writes the user id in rrp2 to rrp1 corrsponding to value field
#!/bin/sh
BEGIN{
FS="|";
while(getline<ARGV[1]>0)
arr[$1]=$2;
delete ARGV[1];
}
{
#print arr[$1];
key=$1;
if(key in arr)
print $1 FS rr FS arr[key] FS;
else
print $0;
}
can any one tell how can i modify this script to write system date into the date field of rrp1
# 5  
Old 08-06-2007
try this,

Code:
awk -F"|" 'BEGIN{ "date" | getline dateVal; OFS="|"; while( getline < "2") { arr[$1]=$2 } }{ for (i in arr) { if ($1 == i) { $2=dateVal; $3=arr[i]} } print }' 1

output Smilie

Code:
VALUE|DATE|USER|
123|||
243|Mon Aug  6 15:33:11 IST 2007|RRP|
432|||

# 6  
Old 08-06-2007
matrix,

i need the date to be in %d-%b-%Y format. Also can you paste your executable script? cos when i tried i am not getting the output
# 7  
Old 08-06-2007
Quote:
Originally Posted by jam_prasanna
matrix,

i need the date to be in %d-%b-%Y format. Also can you paste your executable script? cos when i tried i am not getting the output
Just change the format as required,

Code:
awk -F"|" 'BEGIN{ "date +%d-%b-%Y" | getline dateVal; OFS="|"; while( getline < "2") { arr[$1]=$2 } }{ for (i in arr) { if ($1 == i) { $2=dateVal; $3=arr[i]} } print }' 1

Code:
VALUE|DATE|USER|
123|||
243|06-Aug-2007|RRP|
432|||

Do you get any errors ?

Just run this awk command, you should be getting it
 
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