UNIX for Dummies Questions & Answers

Hi,
I have a shell script in which there is a file
conn_$temp
where $temp has the pid of the shell script.

in this shell script i have an embedded awk script that must read the file

while ((getline < "conn_$temp") > 0)

However due to the "$temp" in the file name, the awk script is unable to open the file.
How can i fix this problem?
basically i need to append the pid to the file name so that for each session the file names will be different.
Thanks for your help in advance.


Himani

Can you post your script please ?

Hi,
This is the script :

temp=`echo $$`
echo $temp

tempvar1=`some values here`
tempvar2=`somme other values here`

diff conndifffile1_$temp conndifffile2_$temp | egrep '^< |> ' | uniq -u > conndifffile3_$temp

awk -v val1=${tempvar1} -v val2=${tempvar2} -F , 'BEGIN {
while ((getline < "conndifffile3_$temp") > 0)
{
if( substr($1,1,1) == "<" )
{
sub(/</,val1,$1)
sub(/ /," , ",$1)
}
else
{
sub(/>/,val2,$1)
sub(/ /," , ",$1)
}
print $1,",",$2,",",$3,",",$4,",",$5
}
}'


Files conndifffile1_$temp conndifffile2_$temp have some values stored in them.

Thanks,
Himani

Try this,

Code:

temp=`echo $$`
echo $temp

tempvar1=2
tempvar2=3

diff conndifffile1_$temp conndifffile2_$temp | egrep '^< |> ' | uniq -u > conndifffile3_$temp

INPUT_FILE=conndifffile3_$temp

gawk -v val1=${tempvar1} -v val2=${tempvar2} -v val3=${INPUT_FILE} 'BEGIN {
while ((getline < val3 ) > 0)
{
if( substr($1,1,1) == "<" )
{
sub(/</,val1,$1)
sub(/ /," , ",$1)
}
else
{
sub(/>/,val2,$1)
sub(/ /," , ",$1)
}
print $1,",",$2,",",$3,",",$4,",",$5
}
}'

Hi,
Its working !!! thanks.
But i have a doubt .. i was naming the files with the pid so
that if different users login then the files for them would be seperate and not interfere with each other.
If the variable INPUT_FILE is assigned the file3 name then wouldnt that
sometimes make files of different users to be lost?

Thanks,
Himani

- No it won't happen because the PID will always be different

Thanks for ur help