UNIX for Dummies Questions & Answers

Hi,

I am using ls command as below to get the list of *.edi files from 2 different subdirectories as1 & as2:

/ntekupal/test$ ls ./as1/*.edi ./as2/*.edi

It is giving me list of edi files in these folders as below :

./as1/6df667.edi ./as2/823ssd3.edi

Now my requirement is to just get the list of files without showing the absolute path like below :

6df667.edi 823ssd3.edi

Thanks
Raj.

find ./as1 ./as2 -name "*.edi" -print | sed 's!^.*/!!'

Cheers,
ZB

Hi ZB,

Thanks for your reply.
It definitely worked. But I have seen a problem there which I did not realize.

Basically what my script does is pick the files from these 2 folders as1 & as2 and after the files are processed they are moved to archive folders in as1 & as2. So your solution is giving me even the files under subfolder 'archive'. I just need the files under as1 & as2.

Can you throw some light on this please.

Thanks,
Raj.

Hi Raj,

Use find's maxdepth operator

Code:

find ./as1 ./as2 -maxdepth 1 -name "*.edi" -print | sed 's!^.*/!!'

Cheers,
ZB