UNIX for Dummies Questions & Answers

Here is a sample code

grep '903' -i user.txt | tail -2 | awk '{print $2}' | sed 's/B//g'

the input file has data as such
903-xxx-xxxxB
903-xxx-xxxxB
It is a dialer file i want to remove the "B"


any help thanks

can you please explain what do you wanna remove

because your code
is alrady working to remove 'B'
so is there anything else you want to remove

you will not get results from the "awk" part, because $2 will be nothing. the field separator is wrong. You can also do it all in awk

Code:

awk '/^903/{gsub(/B$/,"")}{print}' user.txt

Code:

sed -e "s/\(903.*\)B$/\1/g" user.txt

xander, yes the code works but it doesnt terminate if locks up and it also doesnt change the source file. that is what i want to accomplish.here is the part of the file as it apears.


RPNUM: 903-310-7076B

i want to remove the 'B' so the dialer can call the num

my way will remove the num from the output but not the source file
also it freezes.

the other examples didnt seem to works

thanks everybody

thanks for your help.

some of the problems i was having was removing the B from the DOB line. along with the B from the Phone nums.

HOME# cat user2.txt
PT: DARRELL SMITH
PTDOB: 12/15/98
RP: DARRELL SMITH SR
PTSSN: 558-55-1234
RPSSN: 554-55-1234
HMNUM: 213-555-1234B
RPNUM: 213-555-1234
POENUM: 213-555-1234B
HMADDY: 123 A yourstreet Los Angeles CA 90504
POENAME:
POEADDY:
CLIENT: TMC
DOS: 05/07/05

After trying many diff things i changed ghostdog's example and viola

awk '//{gsub(/B$/,"")}{print}' user2.txt


and now th results are in

HOME# awk '//{gsub(/B$/,"")}{print}' user2.txt
PT: DARRELL SMITH
PTDOB: 12/15/98
RP: DARRELL SMITH SR
PTSSN: 558-55-1234
RPSSN: 554-55-1234
HMNUM: 213-555-1234
RPNUM: 213-555-1234
POENUM: 213-555-1234
HMADDY: 123 A yourstreet Los Angeles CA 90504
POENAME:
POEADDY:
CLIENT: TMC
DOS: 05/07/05
HOME#

Thanks GDog