subtraction from date


 
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# 1  
Old 06-19-2007
subtraction from date

hi gurus!
i realize that my question shows my stupidness, but i need your help!

i have:
Code:
s_date=`date +%m-%d-%Y_%I%p`

variable and i need the same, but minus one hour..
what i made:
Code:
s_date=time(`date +%m-%d-%Y_%I%p`) - 3600

but i'm getting:
Code:
daily_exports.sh: line 20: syntax error near unexpected token `('
daily_exports.sh: line 20: `new_date=time()-3600'

also i did:
Code:
new_date=time()-3600
s_date=strftime(`date +%m-%d-%Y_%I%p`, new_date);

etc.. nothing works,
please, help!

Thank you beforehand,
Maria.

Last edited by Yogesh Sawant; 05-20-2010 at 10:50 AM.. Reason: added code tags
# 2  
Old 06-19-2007
Maria,
Date calculation can be very involved as you have to consider
end of month, end of year, leap year, etc.
Here is a thread that can help you in this issue:
https://www.unix.com/answers-to-frequ...rithmetic.html
# 3  
Old 06-19-2007
Oh, thank you for your help!
this is great source!

Thanks,
Maria.
# 4  
Old 06-19-2007
still fighting. I'll really appreciate any help.
thank you,
M.
# 5  
Old 06-19-2007
cool, i found!
Code:
date -d "-1 hour"

works pefectly,
thank you!

Last edited by Yogesh Sawant; 05-20-2010 at 10:50 AM.. Reason: added code tags
 
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