UNIX for Dummies Questions & Answers

I am trying to write an expect script for remote server login. At some point of time I need to telnet based on the output of grep command. Based on the output I need to select the ip address of the server. How can I write an expect script for the same. The output of the grep command is as follows:

172.24.132.2 typhoon-base-active typhoon-base-db-primary
10.42.1.72 sca-ca1-0-datacallp-activeirm
10.42.1.4 sca-ca1-0-datacallp-inactiveirm
10.42.1.73 sca-ca2-0-datacallp-activeirm
10.42.1.9 sca-ca2-0-datacallp-inactiveirm
192.168.24.11 shmm-ptp-active

I need to select the activeirm on ca1 i.e. the second one in the above list. How can I write a script to select from the out of grep command?

check if this helps you:

Code:

[guest@lab guest]$ cat grep_output 
172.24.132.2 typhoon-base-active typhoon-base-db-primary
10.42.1.72 sca-ca1-0-datacallp-activeirm
10.42.1.4 sca-ca1-0-datacallp-inactiveirm
10.42.1.73 sca-ca2-0-datacallp-activeirm
10.42.1.9 sca-ca2-0-datacallp-inactiveirm
192.168.24.11 shmm-ptp-active
[guest@lab guest]$ grep ca1 grep_output | grep '\-activeirm' | cut -d ' ' -f1
10.42.1.72
[guest@lab guest]$