UNIX for Dummies Questions & Answers

I have a file with 3 digit numbers in it formatted as such:
123
065
321

How would I go about seeing if each number is less than 100 and if so outputting it to another file

Yes, I am a bit of a noob. I have tried with grep but I don't think it'll work.

Any general direction would be appreciated then I'll go bang my head into the wall.

Code:

awk '$0 < 100 {print}' infile > newfile

Cheers,
ZB

Thanks. Now just out of curiosity, if I wanted to grab the numbers between 65 and 100 and count them and then between 101 and 450 could I do that in a similar manner.

Also, can awk use the number in a variable in a script rather than a hard coded "100" as in the previous reply. Lastly, do I need to output awk to a file to get the count or can I do it on the fly. I appreciate the help.

something like this

Code:

awk '65<$0 && $0<=100{c1++}
       101<$0 && $<=450{c2++}
END{ 
    print "Count of 65 to 100: " c1
    print "Count of 101 to 450: " c2  
} ' file

Thanks...I managed to get that far this morning. What I am wondering now is can I check to see if a number is less than a variable defined earlier in the script, sort of like below:

FIRST1=65
LAST1=100

awk '(($0 > FIRST1) && ($0 < LAST1))'

you pass in the variable like this:

Code:

awk -v first=$FIRST -v last=$LAST1 '{ }'

I figured it out just as you must have posted this...I had been unaware of the -v option. I really appreciate all of your help. Thanks.