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where is the problem in my sed command....

 
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Top Forums UNIX for Dummies Questions & Answers where is the problem in my sed command....
# 1  
Old 04-20-2007
where is the problem in my sed command....
for example i have the file that contain several line..and i want to swap the first word and the second word than i store it into new file..

on the command i wrote:

Code:
sed -e "s/^\([^]*\)\([^]*\)/\2\1/g" file > swapfile

i think its already correct...
but i got the error

Code:
sed: -e expression #1, char 26:invalid reference \2 on 's' command's RHS

actually whats wrong with this? i am very exhausted...Smilie
# 2  
Old 04-20-2007
actually i already solve it using awk ..

but i am still curious for the sed command...i think we can do it also using sed comand right?
Last edited by P_W; 04-20-2007 at 02:46 PM..
# 3  
Old 04-20-2007
Code:
sed 's/^\([^ ][^ ]*\) \([^ ][^ ]*\)/\2 \1/' file > swapfile

# 4  
Old 04-20-2007
^^
Thanks for the reply..

unfortunately that code doesnt work also..the code only swap the last letter in the word to the front of the word... Smilie

let me find it out....
# 5  
Old 04-20-2007
Are you sure?

Code:
reborg@www:~$ cat file
one two three four five
one two three four five
one two three four five
one two three four five
one two three four five
one two three four five
reborg@www:~$ sed 's/^\([^ ][^ ]*\) \([^ ][^ ]*\)/\2 \1/' file
two one three four five
two one three four five
two one three four five
two one three four five
two one three four five
two one three four five
reborg@www:~$

# 6  
Old 04-20-2007
oh mate...

sorry...it is working...i just miss the [space] there....

thanks...Smilie
 
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