ls command help


 
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# 8  
Old 04-12-2007
awk Thanks sooo much.

My mananger wants to know if their is any way feasible to search for a certain date, (i.e. March 22 2004)?

Or list all files between May 2, 2005 and June 3, 2006.

Stuff like that.

Let me know.

Thanks again awk
# 9  
Old 04-12-2007
The following commands display files between a certain date range:
Code:
## Creates a file with date of 01/Jan/2006 00:00
touch -m 0101000006 $$START_FILE

## Creates a file with date of 01/Jan/2007 00:00
touch -m 0101000007 $$END_FILE

## List files in date order and display only those in between
## $$START_FILE and $$END_FILE
ls -lt | sed -n "/$$END_FILE/,/$$START_FILE/p"

## Remove both temporary files.
rm -f $$START_FILE
rm -f $$END_FILE

# 10  
Old 04-12-2007
How would I now go about deleting those selected files from that certain date range?

Meaning I would like to delete all files from 2006.

Thanks again
# 11  
Old 04-12-2007
ndoggy020,
Did you run the code I wrote above?
Change the "ls" command from "ls -lt" to "ls -1t" and run it.
# 12  
Old 04-12-2007
I did, and it indeed displayed the files within the date range I selected. Im just wondering what command I would use to delete those files?
# 13  
Old 04-12-2007
Listing File between two dates

As mentioned is the previous post,create to files with modification time as that of the date ranges

touch -mt 200505020000 /tmp/May-2-2005
touch -mt 200606030909 /tmp/June-6-2006

And try,
HTML Code:
find <your-dir> -name '*' \( -newer /tmp/May-2-2005 -a ! -newer /tmp/June-6-2006 \) -ls
Hope this helps.

Thanks
Nagarajan Ganesan
# 14  
Old 04-12-2007
Try this -- the "FINAL_rm_FILE" will have all the "rm" commands for each file:
Code:
ls -1t | sed -n "/$$END_FILE/,/$$START_FILE/p" > $$rm_FILE
sed 's/^/rm -f /' $$rm_FILE > FINAL_rm_FILE

 
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