UNIX for Dummies Questions & Answers

hi members...

another new probs...
i need to check all the zip files in the server and check for a space or "`" in the file name and if found need to remove them and form a zip file.

i tried using grep command to check for a space but with out success also when i tried checking for "`" as its a special character its not recognisable in the script .. so need to have escape sequence i suppose ..

i need help to come out of this
please help

Code:

while read file
do

#Following would have the clean name without such chars
#newfile=`echo "$file" | sed "s/[ \`]//g"`

mv $file `echo "$file" | sed "s/[ \`]//g"`

done < list_of_filenames_with_such_chars

Hi,
Try to use egrep as follows
ls *.zip | egrep -e '(" "|\`)'
This will find the files with space or ` in the file name.
If you want to search multiple directories try to use it with find..

Thanks
Raghu

hi matrix...

plz cud u explain the command

mv $file `echo "$file" | sed "s/[ \`]//g"`

also when i execute this command
we got error
unexpected EOF while looking for matching ``'

please help

Could you please post how you had executed the command, with your input, if possible ?

File with spaces and ` character are suppressed and the old file is renamed to new file

hi matrix

here is the file name
3`_1_01_au.zip

and the code

ls *.zip | while read file
do
echo $file
echo "$file" | sed "s/[ \`]//g"
mv $file `"$file" | sed "s/[ \`]//g"`
done

error : mv: missing file argument
and unexpected EOF while looking for matching ``'

try this

Code:

mv $file $( echo "$file" | sed "s/[ \`]//g" )