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regarding replace a part of a string

 
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# 1  
Old 02-22-2007
regarding replace a part of a string
hi all.

i have a file name like abcd_vbnh.a_p
i have to copy it as abcd_vbnh.a every time...

in unix not in perl please
# 2  
Old 02-22-2007
Code:
a=abcd_vbnh.a_p
echo ${a%_*}

# 3  
Old 02-22-2007
MySQL
Hi Madan,
Could you please explain the below one please?

{a%_*}

Ganapati.
# 4  
Old 02-22-2007
Quote:
Originally Posted by ganapati
Hi Madan,
Could you please explain the below one please?

{a%_*}

Ganapati.
Extracts the value before the last hyphen Smilie
# 5  
Old 08-04-2008
Mid of String
How can i get the Sub string of a String

My parent String is a file name which is namely "US_SALES_08_2008_I.csv"
now i wanted to retrieve substring that is before .csv but after "_"


that is it needs to retrieve "I" in this case.

Kindly help me out. i am struck.

Regards,
Swapna
# 6  
Old 08-04-2008
Hammer & Screwdriver What about this approach?
Code:
> infile=US_SALES_08_2008_I.csv
> echo $infile
US_SALES_08_2008_I.csv
> echo $infile | tr "_" "\n" | tail -1
I.csv

> infile=US_SALES_08_2008_IJKLM.csv
> echo $infile
US_SALES_08_2008_IJKLM.csv
> echo $infile | tr "_" "\n" | tail -1
IJKLM.csv

or, if just looking for the part before the '.'
Code:
> infile=US_SALES_08_2008_I.csv
> echo $infile | tr "_" "\n" | tail -1 | cut -d"." -f1
I
> infile=US_SALES_08_2008_IJKLM.csv
> echo $infile | tr "_" "\n" | tail -1 | cut -d"." -f1
IJKLM

# 7  
Old 08-04-2008
Hey thanks buddy,

I wanted to get I which is through cut and tail. It worked thanks a lot. for ur help. I was searching since morning.

Swapna
 
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