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How to replace ??

 
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# 1  
Old 02-09-2007
How to replace ??
Hi all,
I have a file with the following data.

E01011U, ,E11, , , ,0
E03012U, ,E14, , , ,0
E02013U, ,E25, , , ,0

I want to change it to

('E01-01-1-U','E11' );
('E03-01-2-U','E14' );
('E02-01-3-U','E25' );

Please let me know about it .Thanks in advance.
# 2  
Old 02-10-2007
Try this:
Code:
awk -F, '{ printf "\(\47%s-%s-%s-%s\47\,\47%s\47\)\;\n",  substr($1,1,3) , substr($1,4,2) , substr($1,6,1), substr($1,7,1) , $3 }' inputfile

# 3  
Old 02-10-2007
What have you tried so far ? Smilie


Code:
sed "s/\(.\{3\}\)\(.\{2\}\)\(.\{1\}\)\(.\{1\}\), ,\(.\{3\}\)\(.*\)/(\'\1-\2-\3-\4','\5');/" filename

# 4  
Old 02-11-2007
MySQL Thanks, both.
hey thanks both.
Well I used awk itself and then use some commands in the vi and got the desired result but it was an round about method Smilie
# 5  
Old 02-19-2007
Help needed again !!
Hi I am stuck again.
I have
Z22-01-0-1 Z22-01-1-A XXX Z03 Z48 ZP7 ZP2 10 0 1
I need
insert into templocs ('Z22-01-1-A','Z22-01-0-1','L','Z03','Z48','ZP7','ZP2);

At the third field I need "L" instead of XXX.I found out that for singlr quotes 47 is the ASCII value but was not successfull in making a command out of it.

Please help me.
Thanks and Regards,
Gideon.
# 6  
Old 02-19-2007
Here is an ugly way of doing it, Smilie

Code:
echo "Z22-01-0-1 Z22-01-1-A XXX Z03 Z48 ZP7 ZP2 10 0 1" | sed "s/\(.*\) \(.*\) \(.*\) \(.*\) \(.*\) \(.*\) \(.*\) \(.*\) \(.*\) \(.*\)/insert into templocs ('\2','\1','L','\4','\5','\6','\7');/

# 7  
Old 02-19-2007
Code:
echo "Z22-01-0-1 Z22-01-1-A XXX Z03 Z48 ZP7 ZP2 10 0 1" |
sed "s/XXX/L/;s/ /','/g;s/^/insert into templocs ('/;s/$/');/"

 
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