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backing up file everytime script run and saving other backups

 
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# 1  
Old 01-28-2007
backing up file everytime script run and saving other backups
how would i go about creatng a backup of a file everytime a script is run so that the next time it is run the old backup gets pushed back and the most recent backup is 1st.
(new)backup.1
(old)backup.2
that kind of idea??
# 2  
Old 01-28-2007
Code:
if [ $i -le $c ]
        then
                echo "Creating Backups..."

                if [ -f $f.1 ]
                then
                        cp -v $f.$i $f.$j
                        rm $f.$i
                        cp -bv usermon $f.$i
                        sleep $s
                        ((i=i+1))
                else
                        cp -bv usermon $f.$i
                        sleep $s
                        ((i=i+1))
                fi
        fi

this is what i have so far...but obviously it only works for 2 backups..i need to be able to have an endless number
# 3  
Old 01-29-2007
Quote:
Originally Posted by knc9233
if [ $i -le $c ]
then
echo "Creating Backups..."

if [ -f $f.1 ]
then
cp -v $f.$i $f.$j
rm $f.$i
cp -bv usermon $f.$i
sleep $s
((i=i+1))
else
cp -bv usermon $f.$i
sleep $s
((i=i+1))
fi
fi
From where values of variables i, c, j are comming, please post a complete copy of your script.
# 4  
Old 01-29-2007
Something like this might help:
Code:
$ cat saver
#! /usr/bin/ksh

max=10
i=$max
while ((i>0)) ; do
        ((i=i-1))
        ((i2=i+1))
        echo "[[ -f somelog.$i ]] && cp somelog.$i somelog.$i2"
done
echo "cp somelog somelog.0"
exit 0
$ ./saver
[[ -f somelog.9 ]] && cp somelog.9 somelog.10
[[ -f somelog.8 ]] && cp somelog.8 somelog.9
[[ -f somelog.7 ]] && cp somelog.7 somelog.8
[[ -f somelog.6 ]] && cp somelog.6 somelog.7
[[ -f somelog.5 ]] && cp somelog.5 somelog.6
[[ -f somelog.4 ]] && cp somelog.4 somelog.5
[[ -f somelog.3 ]] && cp somelog.3 somelog.4
[[ -f somelog.2 ]] && cp somelog.2 somelog.3
[[ -f somelog.1 ]] && cp somelog.1 somelog.2
[[ -f somelog.0 ]] && cp somelog.0 somelog.1
cp somelog somelog.0
$

# 5  
Old 01-29-2007
You could just put a date stamp on the end of the file in YMDHMS order.

mv filename to filename.`date +%Y%m%d%H%M%S`
When you do ls -l it should sort in date order.

To drop the older files by date, use the find command

find /directory -filename* -mtime -30 -exec rm {} \;

If you want to keep n number of copies:

cd directory
VAL=`ls -l -1 -t filename* | wc -l`
VAL=`expr ${VAL} - 738`
FILES=`ls -1 -t filename* | tail -${VAL}`

for file in $FILES
do
echo "Deleting file $file...."
rm -f $file
done
 
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