UNIX for Dummies Questions & Answers

Thanks!! Its ok but i am able to transfer files on remote host through scripting the problem i have is in counting number of files ftped there on remote host.

please see the 4th post from Shiv_jad to this thread.
waiting for favorable solution.
shiv

Redirect your ftp output to a ftp_log file and parse the file to get the file count from there

Code:

ftp -nv $HOST <<EOF1 >>some_ftp_log.log

Thanks for your quick reply madhan, but its giving me error as file can not be created. my script is as follows.


ftp -v -n $HOST_NAME <<cmd >>LOGFILE
user $HOST_USERNAME $HOST_PASS
cd /data_ca/ftpdir
mput *
nlist
#get count of files ftped to this location
quit
cmd

Also tell me where this LOGFILE should be created? the path from where i am running the script on local host?? Also i want the count of files ftped to the remote host. so suggest the code to be included below the commentline in above code.

Thanks
Shiv@jad

You can create the file anywhere which is comfortable to you .
If you are not able to create the log file, check for the permissions and work out appropriately.
In the log file, there would be file transfer message, you need to grep that count and you would have the files transferred.

Matrix is right on. If you can't create a log file permissions is most likely the issue. Here is a script I created doing what you want. The count issue you will get by sorting through the log file created.

#!/bin/sh
#set -v
echo NOTE: check ftplog for connection info
rm ftplog
date >>ftplog

HOST='192.168.0.214 5021'
USER='user01'
PASSWD='user01'
FILE='/home/dude/file.txt'

ftp -v -n $HOST >>ftplog 2>&1 <<EOJ
quote USER $USER
quote PASS $PASSWD
debug
pwd
passive
pwd
put $FILE
ls
close
bye
EOJ
exit 0

You can use /tmp for your log file and you won't have access problems there.
So the script above would look like this

Code:

#! /bin/sh
#set -v

HOST='192.168.0.214 5021'
USER='user01'
PASSWD='user01'
FILE='/home/dude/file.txt'
FTPLOG='/tmp/ftplog'

echo "NOTE: check ftplog for connection info"
date > $FTPLOG

ftp -v -n $HOST >> $FTPLOG 2>&1 <<EOJ
quote USER $USER
quote PASS $PASSWD
debug
pwd
passive
pwd
put $FILE
ls
close
bye
EOJ
exit 0

Thanks All
It worked fine.but please clear my concepts what is '2>$1' means?
what purpose is solved by writing debug?
and what does set -v do? How does it will affect the functionality if i wont include these parameters.

Please help me to clear my doubts.
Thanks a lot!!
Shiv@jad