UNIX for Dummies Questions & Answers

Hi,

I would like to display a sorted list (based on the login name) of the login name, the home directory and the default shell of each user defined on the system ;

I just do
cut -d: -f1,6,7 /etc/passwd | sort


And then I would like to separate each information with a space character.
I had the idea to use the Outpud Field Separator as I use with awk but no way .
How could I like this space with this command ?

thanks .

perhabs:

# cut -d":" -f 1,6,7 < /etc/passwd | tr ':' ' '

or the awk way:

# awk -F\: '{printf "%s %s %s\n",$1,$6,$7}' /etc/passwd

regards pressy

thanks so much