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For Loop and concetnating values in a variable

 
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# 15  
Old 09-29-2006
Thanks all of you for the various solutions.

Appreciate your help
# 16  
Old 10-02-2006
Hi Ygor,

I tried using this

grep emailkey1 abc.txt | cut -d: -f2 | paste -s -d,

However it errored out saying

paste: Usage: paste [-s] [-d List ] File1 ...
# 17  
Old 10-02-2006
It worked for me. Perhaps your version of paste needs space between "-d" and ","?
# 18  
Old 10-03-2006
Quote:
Originally Posted by vgersh99
one way:
Code:
nawk -F: -v OFS=',' -v key='emailkey1' '$1==key {arr[key] = (key in arr) ? arr[key] OFS $2 : $2} END {print arr[key]}' abc.txt

Dear vgersh99,

I have one question about your code, normally we refer to an array by the subscript where subscript is a number, but in your code you have used arr[key] where key='emailkey1' how it works? and how awk keeps track of subscript in that case? And while printing also you have used the same thing that print arr[key] and it prints all the elements of array based on subscript arr[emailkey1], its really confusing for me.

Your explanation would be highly appreciated.

Cheers,
An Awk student
# 19  
Old 10-03-2006
Quote:
Originally Posted by Glenn Arndt
My method is similar (not as slick), but doesn't use arrays...
Code:
awk -F: -v key="emailkey2" '
 BEGIN { addrlist=0 }
 $1 ~ key {
   addr=$2
   if (addrlist == 0) {
     addrlist=addr
   } else {
     addrlist=addrlist "," addr
   }
 }
 END { print addrlist }' abc.txt

Dear Glen,

Just want to clarify one thing about $1 ~ key, that here match operator ~ was not required, because as per my understanding, match operator is required only in case where we have to compare a value against a regular expression, for comparing values against variables or constants we can use something like $1==key am I right?

It would be hightly appreciated if you can elaborate the detailed use of match operator ~

Cheers,
An Awk student
# 20  
Old 10-03-2006
Quote:
Originally Posted by nervous
Dear vgersh99,

I have one question about your code, normally we refer to an array by the subscript where subscript is a number, but in your code you have used arr[key] where key='emailkey1' how it works? and how awk keeps track of subscript in that case?
awk's arrays are associaitive in nature where the subscript is a 'string' and not necessarilly a 'number'.
Quote:
Originally Posted by nervous
And while printing also you have used the same thing that print arr[key] and it prints all the elements of array based on subscript arr[emailkey1], its really confusing for me.
Iterating through an array based on its subscriipt [a 'key'] we print the content of every array cell [its 'address'].
# 21  
Old 10-03-2006
Quote:
Originally Posted by nervous
Dear Glen,

Just want to clarify one thing about $1 ~ key, that here match operator ~ was not required, because as per my understanding, match operator is required only in case where we have to compare a value against a regular expression, for comparing values against variables or constants we can use something like $1==key am I right?

It would be hightly appreciated if you can elaborate the detailed use of match operator ~
That is correct. I suppose I used "~" out of habit or by mistake. While correct in this case, I'd probably agree that "==" would be the more technically appropriate operator.
 
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