UNIX for Dummies Questions & Answers

I need to calcualte the size of a directory [and all it's subdirectories] by the year the files in that directory were created [or last accessed].
For example the script will sum up, by year, the number of blocks for that directory and its' subdirectories for files created / accessed in that year.

I need a report that would look like this :-
year 2000 50000 blocks
year 2001 2000 blocks
year 2002 45000 blocks
year 2003 150 blocks ...etc...etc thru year 2006.

I think I need to do this usings awk, but I'm not certain.

any ideas?

Thanks,
igidttam

I'm close but I don't have it right yet.
The code below prior to the pipe du -ks gives me all the files for 2002.
I just want the total bytes for those files for 2002

ls -rRl | awk '$8=="2002" ' | du -ks


Thanks
igidttam

Code:

find . -type f -ls | nawk '{arr[$8] += $7} END {for (i in arr) printf("%s -> [%d]\n", i, arr[i])}'

If I use this, I get the total at the end. This worked for 2003 files

ls -rRl | awk '$8=="2003" ' | du -k -a

du command won't take input which you passed through pipe

I tried your code and it doesn't total by year. It does it by month.
Looks like it's all the same. There should be a different number of total bytes per year


> find . -type f -ls | nawk '{arr[$8] += $7} END {for (i in arr) prin
tf("%s -> [%d]\n", i, arr[i])}'

Apr -> [2147483647]
Jun -> [2147483647]
5 -> [0]
25 -> [0]
Oct -> [2147483647]
Sep -> [2147483647]
Nov -> [2147483647]
Mar -> [2147483647]
May -> [2147483647]
Dec -> [2147483647]
Jan -> [2147483647]
Aug -> [2147483647]
Jul -> [2147483647]
Feb -> [2147483647]

yes I realize that now. Do you know how I can accomplish this?