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capturing the time stamp

 
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# 1  
Old 07-18-2006
capturing the time stamp
Hi All,

I am working on a korn shell script.
i have a file such as:
DS.PETSCO.20060601203514.20060531.ctl_20060717124431

i have 2 problems here.

1) i have to capture the time stamp from
the above file i.e this number 20060717124431.
format of time stamp is YYYYMMDDHHMMSS.

can anyone plz let me know how do i capture the time stamp.

2) the second problem is, i have to calculate the next 27 hours
from the above time stamp.

SAY time in the above timestamp is 12:44:31 so i have to add
27 hours to this time stamp.

Note:when i add 27 hours please note that date also changes.
so i have to echo the new date and time when i add 27 hours
to the exisitng time stamp.

can anyone plx let me know how I do it.

thanks
pavi
# 2  
Old 07-18-2006
Use cut to get the time stamp.
Code:
echo "DS.PETSCO.20060601203514.20060531.ctl_20060717124431"|cut -d_ -f2

A shell script could then help you add the 27 hours to that datestamp... can't help you with that right now, cause I don't have access to a unix box.
# 3  
Old 07-18-2006
capturing the time stamp
Thanks a lot.

can anyone plz help me

thanks
pavi
# 4  
Old 07-18-2006
I would use ksh's built-in pattern matching to get the time stamp, which is everything after the "_":
Code:
$ file=DS.PETSCO.20060601203514.20060531.ctl_20060717124431
$ echo ${file##*_}
20060717124431
$

Calculating 27 hours from the time stamp is another matter, although here's one way to look at it -- 24 hours from the time stamp is going to be the same time, just 1 (or possibly 2) day(s) later, so just add 3 hours. For date arithmetic, see Perderabo's datecalc script.
# 5  
Old 07-18-2006
Code:
#!/bin/ksh
# add 27 hours to a "timestamp"

timestamp=$(echo "DS.PETSCO.20060601203514.20060531.ctl_20060717124431"|cut -d_ -f2 )
perl -e '
        use Time::Local;
        
        $tm="$ARGV[0]";
        $sec=substr($tm,12,2);
        $min=substr($tm,10,2);
        $hr=substr($tm,8,2); 
        $day=substr($tm,6,2);
        $month=substr($tm,4,2);
        $yr=substr($tm,0,4);        
        $epochtm=timelocal($sec,$min,$hr,$day,$month,$yr);
        $hours=$ARGV[1];
        $epochtm=$epochtm + ($hours * 3600);
        $now=localtime $epochtm;
        print "$now", "\n";        
        ' "$timestamp"  27

 
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