UNIX for Dummies Questions & Answers

Dear all,

Every hour i am receiving several data files to one folder for 24 hours each day.But some times some hours i do not have the files because of some problem.So i want to check the files inside the folder at the end of the day wether how many files i received in each hour like this.so i know if the files are missing , since missing hour files received is zero.

results should be like this,

00 hour - 15 files
01 housr - 14 files
02 hour - 10 files
-
-
23 hour - 5 files

can some help me to write a script for this ?


Nayanajith.

what is the filenaming convention ?

or they created based on the hour they are created ?

if they are not modified, with the access time (which would be the same as creation time) also we can generate a requested list

reply

They are created based on the hour.

eg,

Jun 22 23:12 0622.IST230500.00.pp_20060622_231252
Jun 22 23:22 0622.IST231000.00.pp_20060622_232223
Jun 22 23:22 0622.IST231500.00.pp_20060622_232252
Jun 22 23:42 0622.IST233500.00.pp_20060622_234252
Jun 22 23:52 0622.IST234000.00.pp_20060622_235222
Jun 23 00:02 0622.IST234500.00.pp_20060623_000252
Jun 23 00:03 0622.IST235000.00.pp_20060623_000322
Jun 23 00:12 0623.IST000000.00.pp_20060623_001252
Jun 23 00:22 0623.IST001000.00.pp_20060623_002222

so i have 5 files on 22nd and i have 4 files on 23rd.

Result should be,

Jun 22 23 hour - 5 files
Jun 23 00 hour - 4 files.

so i want a script get above result.

Thanks.

Try this

>ll * |grep Jun |grep 22 |grep 23: |wc -l

above cmd will give you number of files created on Jun 22, 23hours. You can replace * with the file name pattern for specific files.

Hi Naynajith

I am not sure is this one exctly you want. Any way hope that at least it will help you derive what you are looking for.

Here is the script I tried and as per my understanding of your question, it works!!!

#/bin/ksh
for i in "00" "01" "02" "03" "04" "05" "06" "07" "08" "09" "10" "11" "12" "13" "14" "15" "16" "17" "18" "19" "20" "21" "22" "23"
do
count=`ls -l | grep " $i " | nawk -v arg="$1" '{if(index($8,arg) == 1) print $0' | wc -l`
echo "Hour $i - $count File(s)"
done


The script accepts the date as runtime argument. For example I saved it as t.sh, then I did run the script as follows to get the report for Jun 26

$t.sh "Jun 26"


Hope it helps you!!