Date Reformat


 
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# 1  
Old 04-24-2006
Question Date Reformat

Hello,

I have a .CSV file with 10+ datetime columns. The way the data is stored
in these columns are -

4/4/2006 3:45:30 PM

I want the single digits to be left padded with a zero so the above looks like

04/04/2006 03:45:30 PM

As the dates and times are different throughout the file manually changing
it in the file with a find and replace is not considered.

Any function/command to achieve this will be appreciated. Thanks.

Rgds,
F1
# 2  
Old 04-25-2006
This is GNU sed, and not thoroughly tested...
Code:
$ echo 'field1,4/4/2006 3:45:30 PM,f3,4,etc'>file1
$ sed -e :a -e 's!\([^0-9]\)\([0-9]\)\([/:]\)!\10\2\3!;ta' file1
field1,04/04/2006 03:45:30 PM,f3,4,etc

# 3  
Old 04-25-2006
Thanks YGOR

This solution helped. Thanks mate. Much appreciated.
 
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