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CUT Command

 
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# 8  
Old 03-23-2006
CUT Command
Quote:
Originally Posted by gauravgoel
do the following things,

1) instead of redirecting it to tempfile, display the variables on terminal and see if they are getting displayed.
a)Have tried this by assigning (hard coding) the value to a variable and it working fine.

b) If I write a value to variable by looping, it prints nothing on the screen. However, it takes some time to return me to shell prompt. (as if working).

Quote:
Originally Posted by gauravgoel
2) if the step 1 is not working then post your script and the output after running it using set -x.
I am really sorry, but I don't know how and where to use this option.

I will really appreciate your feedback on this.

Thanks and best regards

Shoeb
# 9  
Old 03-23-2006
Code:
#! /bin/ksh

typeset -L4 tmp
typeset -L8 tmp1
typeset -L6 tmp2

while read initial
do
        tmp=$initial
        initial=${initial#$tmp}
        tmp1=$initial
        initial=${initial#$tmp1}
        tmp2=$initial
        initial=${initial#$tmp2}

        echo "$tmp $tmp1 $tmp2"

done < input.txt

Since your boundaries for cut are fixed, so the typeset lengths are fixed i.e.
typeset -L4 tmp == cut -c 1-4
typeset -L8 tmp1 == cut -c 5-12
typeset -L6 tmp2 == cut -c 13-18
# 10  
Old 03-23-2006
Hi,
Just check if the code given by vino works. if it doesn't then

the set -x option is used to run the script in debug mode.
write this after #! line i.e. first line of the script and then run the script.
post both the script and the output. Keep the no. of iterations of loop small otherwise the output will be very large

Gaurav
# 11  
Old 03-23-2006
one more thing I have just tried the following and its working fine

Quote:
echo "1 2 3
2 3 4 5"|while read line
do
echo $line
val=$1
tmp=`echo $val|cut -c 1-4`
tmp1=`echo $val|cut -c 3-6`
echo $tmp $tmp1
done
pass the string as a parameter to string and the values are properly CUT.

Gaurav
# 12  
Old 03-23-2006
CUT Command
This is the output if I assign the value to the variable in the script.

Code:
# ./n5
val=162002/02/06226275
+ echo 162002/02/06226275
+ cut -c 1-4
tmp1=1620
+ echo 162002/02/06226275
+ cut -c 5-12
tmp2=02/02/06
+ echo 162002/02/06226275
+ cut -c 13-18
tmp3=226275
+ echo 1620 02/02/06 226275
1620 02/02/06 226275

I think there is something wrong with the code below: (p.s. I dont know my pipelined awk and head -2 will work in sh or not)

Code:
set -x

awk {'print $1'} d15| head -2| while read line
do
val=$1
tmp1=`echo $val|cut -c 1-4`
tmp2=`echo $val|cut -c 5-12`
tmp3=`echo $val|cut -c 13-18`
echo $tmp1 $tmp2 $tmp3  >> t4
done

The o/p is below:

Code:
val=
+ echo
+ cut -c 1-4
tmp1=
+ echo
+ cut -c 5-12
tmp2=
+ echo
+ cut -c 13-18
tmp3=
+ echo
+ read line
val=
+ echo
+ cut -c 1-4
tmp1=
+ echo
+ cut -c 5-12
tmp2=
+ echo
+ cut -c 13-18
tmp3=
+ echo
+ read line

Vino, I have tried your code, its o/p is as below:

Code:
1809 01/02/06 01/02/
1814 01/02/06 01/02/

Can you suggest why it is not assigning value to tmp2. Also, can you please tell me how can I redirect o/p of the script you have given to a file. I mean redirect is ">>" only in KSH or something diff.

Also, I am sorry but I am not familier with KSH, can you suggest me a link where I can understand your code.

Best Regards

Shoeb
Last edited by shoeb_syed; 03-23-2006 at 04:29 AM.. Reason: some more addition
# 13  
Old 03-23-2006
Hey man what are you exactly doing,

your val=$1 expects a commandline parameter.
since you are not passing the commandline parameter the value is not getting set, and thats why the blank output is coming.

To me it seems that you are confused between $1 of awk and $1 you are trying to set in val. Both are different.
Correct me if I am wrong

Gaurav
Last edited by gauravgoel; 03-23-2006 at 04:33 AM.. Reason: typo
# 14  
Old 03-23-2006
CUT Command
I am sorry Gaurav, but I really thought that both are same. I hope you will forgive me for my lack of knowledge.

Can you please correct me how can I pass command line parameter.

Thanks & Best Regards

Shoeb
 
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