UNIX for Dummies Questions & Answers

Is there any cut or awk function that would allow me to take the last part of a path away and save the list into a file? I wrote:
find $HOME -mtime +3 > fileList

cat fileList
/home/102/s/jn/folder/HW
/home/102/s/jn/otherfolder/B.txt
/home/102/s/jn/folder4/3dA/w
/home/102/s/jn/folder5/3dAnim/tr.mt

but I only need the file names and not the whole path. =( I would imagine you would have to set the delimiter to "/" but there is no specific field number since I want to look in all directories and sub directories.

Using shell builtins.

Code:

while read line
do
echo ${line##*/}
done < input.txt

If you need to combine it with the find command, then you need to probably use basename