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Extract directory name from the full directory path in UNIX using shell scripting

 
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# 1  
Old 06-03-2014
Extract directory name from the full directory path in UNIX using shell scripting
My input is as below :

Code:
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/loyal/IFIND.HELLO.WROC.txt
/splunk/scrubbed/triumph/ifind.triumph.txt

From the above input I want to extract the file names only .
Basically I want to extract anything after 4th slash (/) , as the file will always be under third directory .
Last edited by IshuGupta; 06-03-2014 at 08:01 PM..
# 2  
Old 06-03-2014
Code:
filepath="/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt"
echo ${filepath##*/}

---------- Post updated at 04:50 PM ---------- Previous update was at 04:46 PM ----------

Code:
while read f; do echo ${f##*/}; done < filelist

This User Gave Thanks to Aia For This Post:
IshuGupta
# 3  
Old 06-03-2014
Thanks a bunch Aia.....it works..... when you get time...can you please tell me how ##*/ works
# 4  
Old 06-03-2014
Quote:
Originally Posted by IshuGupta
Thanks a bunch Aia.....it works..... when you get time...can you please tell me how ##*/ works
## (2#) to match as much of the pattern (in this case */) and strip it, starting from the beginning
There are also:
# (1#) same that ## except that it will match as less as possible (no greedy)

If you want to start from the end of the content, then you use % or %%
This User Gave Thanks to Aia For This Post:
IshuGupta
# 5  
Old 06-03-2014
Great...it absolutely looks like a machine language. Smilie
# 6  
Old 06-03-2014
Quote:
Originally Posted by IshuGupta
Great...it absolutely looks like a machine language. Smilie
The language is called the shell command language. It is defined on your shell's man page. This part of the language is described in a section called parameter expansion; ${var##*/} is described in a subset of that portion of the language known as variable expansion.
 
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