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Grep for list of files with only found hits

 
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# 1  
Old 05-14-2014
Grep for list of files with only found hits
Hi,

With grep -ci word * I get a list of files either they have a hit, or the have not (0).

I wanted to pipe to a new list of files, which only shows the files where the string was found, and counted, not the whole bunch.

How to do this?

Any advice welcome!


with best regards,
Omar K N
Stockholm, Sweden
# 2  
Old 05-14-2014
Can you show an example.
And remember to wrap your commands and output with CodeTags - this makes it much easier to read.
# 3  
Old 05-14-2014
Use -l option (--files-with-matches)
# 4  
Old 05-14-2014
Thank you Yoda,

Yes grep -l shows a list of files-with-matches,
but it doesn't tell how many matches in each file.

So there has to be set in a count of some sort, maybe by piping from
Code:
grep -ci word * |*…

# 5  
Old 05-14-2014
May be something like this:
Code:
grep -ci word * | while read line; do
if [ ${line#*:} -gt 0 ]; then
 printf "%s\n" "$line"
fi
done

This User Gave Thanks to xbin For This Post:
OmarKN
# 6  
Old 05-14-2014
Alright, ... I see have to put this in a shell script first,-

/okn
# 7  
Old 05-14-2014
Actually no, you can type it into your shell and have it work too. It's the same thing.
This User Gave Thanks to Corona688 For This Post:
OmarKN
 
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