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How to grep particular line from a file?

 
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# 8  
Old 05-12-2014
I have provided 3 for n, you can change as per your requirement
Code:
 
awk 'NR == n' n='3' file

This User Gave Thanks to SriniShoo For This Post:
sumanthupar
# 9  
Old 05-12-2014
Quote:
Originally Posted by sumanthupar
if user give 3(Line number) as input then it should grep the contents in the 3rd line
The probably fastest is to quit immediately after finding the line:

Code:
iLinNr=3
sed -n "$iLinNr {;p;q;}" /path/to/file

I hope this helps.

bakunin
# 10  
Old 05-12-2014
Some of us were confused by your use of the term grep.

The name of the grep utility is a play on the ed utility's Global search for a Regular Expression and Print matching lines command:
Code:
g/RE/p

Your description does not perform a global action and has no regular expression (or anything else to search for); so it seemed like something was missing.

If you had just said that you want to print (or extract) a single line specified by a user supplied line number from a file, you would have gotten what you wanted faster.
This User Gave Thanks to Don Cragun For This Post:
sumanthupar
# 11  
Old 05-14-2014
Thanx a lot to all..........It's working.........
 
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