Produce the number 2014 without any numbers in your source code...


 
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# 15  
Old 04-28-2014
Using modes (GNU stat version):
Code:
>f; chmod =,g=xs,o=r f; stat -c %a f

Regards,
Alister
# 16  
Old 04-28-2014
Ha ha...
OK, bending the rules...
Code:
echo MMXIV

# 17  
Old 04-28-2014
Code:
yes | (echo $((head; head) | wc -l)$((head; sed 'n;n;n;q') | wc -l))

Regards,
Alister
# 18  
Old 04-28-2014
Quote:
Originally Posted by bakunin
Shouldn't the obvious solution in shell be:

Code:
# cat ~/riddles/misc/solution.txt
2014
# _

This could be squeezed down to 5 bytes using an sufficiently short filename. ;-))

bakunin
Haha, unfortunately someone hath foreseen your cunning plan:
Quote:
...make a program that prints the number 2014, without using any of the characters 0123456789 in your code, and independently of any external variables such as the date or time or a random seed.
Smilie

Otherwise we could go: awk -v v=2014 'BEGIN{print v}'
# 19  
Old 04-28-2014
Code:
$ echo "MjAxNAo=" | openssl base64 -d
2014

$

# 20  
Old 04-28-2014
Quote:
Originally Posted by Corona688
Code:
$ echo "MjAxNAo=" | openssl base64 -d
2014

$

Bzzzzt! base64 Smilie

Regards,
Alister
# 21  
Old 04-28-2014
Curses, foiled again!
 
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