UNIX for Dummies Questions & Answers

Hi

I think this should be relatively simple but I can't figure it out. I have several files with the same name in different folders within a directory (the output of a program that I ran). Something like this:

./myAnalysis/item1/round1/myoutput.txt
./myAnalysis/item1/round2/myoutput.txt
./myAnalysis/item2/round1/myoutput.txt
./myAnalysis/item2/round2/myoutput.txt

I would like to search the myAnalysis directory for all the myoutput.txt files, rename them to include the item and round number from their pathnames and then COPY them to another directory (e.g. leaving the original files/structure intact as that in turn is configured for input into another program).

so I want a new folder with the following files

./newFolder/item1_round1_myoutput.txt
./newFolder/item1_round2_myoutput.txt
./newFolder/item2_round1_myoutput.txt
./newFolder/item2_round2_myoutput.txt

Any suggestions?

Thanks!

Code:

#!/bin/bash
cd /path/to/myAnalysis
[ -d ../new_folder ] || mkdir ../newfolder   # make directory if needed
find .  -type f -name 'myoutput.txt' |
while read fname
do
  newname=$(echo "$fname" | sed 's#/#_#g' | sed 's/^\._//' )
  cp fname ../new_folder/${newname}
done

Start with this example. This can be done several other ways.

Thanks for this jim mcnamara

I had a few problems with the while loop so I ran it in a for a loop and it worked perfectly:

Code:

for i in `find .  -type f -name 'myoutput.txt'`
do newname=$(echo $i| sed 's#/#_#g'| sed 's/^\._//')
cp $i ../new_folder/${new name}
done