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How to Set crontab for 4th and 25th of every month?

 
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# 1  
Old 04-01-2014
How to Set crontab for 4th and 25th of every month?
Hello,

I wanted to set Crontab for 4th and 25th of every month at 5:00 PM.

Script should take previous month and current year as command line arguement like...
Code:
/home/test1.sh -f ABCD 03 2014

so above script will run on 4th and 25th April 2014 but argument should be like previous month i.e 03.
Last edited by vbe; 04-01-2014 at 10:12 AM..
# 2  
Old 04-01-2014
You can use a list in the day-of-month field, like 4,25, so the crontab entry should look like 0 17 4,25 * * /home/test1.sh -f ABCD.
I'm afraid arguments can't be modified, so you need to calculate the values needed in the script itself.

EDIT: Maybe you can use a wrapper script that calls your initial script with that calculated date?
# 3  
Old 04-01-2014
Thanks Rudi,

Cant we do `date '+%m'`-1 or somewhat like calculations or

or can you please give me the code for wrapper script or inside the script modification..
# 4  
Old 04-01-2014
You can put your date commands inside your script and they should work fine. If you are calling supplied/compiled code, you will need to write a script to call it with the correct parameters and get cron to schedule your script.



Robin
# 5  
Old 04-02-2014
Any other expert advice/ Suggestion to pass previous month to script .
Any big head in Shell scripting..

As its a AIX so `date -d -1month +%Y%m` this one is also not working..

how to write wrapper script...

Please help!
# 6  
Old 04-02-2014
IN AIX , I have also faced same problem for getting previous date .

I am using following codes .

Code:
year=`date +%Y`
m=`date +%m`
month=`expr "$m" - 1` 
if [ "$month" -le "10" ] ; then
pmonth=0`echo $month`
else
pmonth=`echo $month`
fi
if [ "$month" == "0" ] ;then
pmonth=12
year=`expr "$year" - 1`
fi
echo $year
echo $pmonth

This may be helpful to you .
# 7  
Old 04-02-2014
On AIX you should have the kornshell 93 installed as /bin/ksh. With this shell you can simplify the code to
Code:
printf "%(%Y %m)T" "1 month ago" | read year month
echo $year
echo $month

This User Gave Thanks to hergp For This Post:
rbatte1
 
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