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Grep for uncomented lines

 
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# 1  
Old 02-24-2014
Grep for uncomented lines
Hi,

I have the below in the hello.txt

Code:
http://google.com
#http://yahoo.com
https:gmail.com

I need to grep for "http" but ignore the second line that is commented because of the '#'

Can you help me with the grep condition ?
# 2  
Old 02-24-2014
Code:
grep "^http" file

This User Gave Thanks to Yoda For This Post:
mohtashims
# 3  
Old 02-24-2014
Code:
$ grep '^http'  file

Code:
$ awk '/^http/' file

if only http then
Code:
$ grep -w '^http' file

This User Gave Thanks to Akshay Hegde For This Post:
mohtashims
# 4  
Old 02-24-2014
Quote:
Originally Posted by Yoda
Code:
grep "^http" file

Sorry, let me correct my file entry as the suggestions fail for the below conditions.

Can you help me with this new condition.

Code:
siebel_url=http://google.com 
#siebel_url=http://yahoo.com 
portal_value=https://gmail.com

I need to grep for 'http' but the result should not have the second line as it is commented by the '#' letter.
# 5  
Old 02-24-2014
Code:
awk '/http/&&!/^#/' file

This User Gave Thanks to Yoda For This Post:
mohtashims
# 6  
Old 02-24-2014
Try :

Code:
$ cat file
siebel_url=http://google.com #siebel_url=http://yahoo.com portal_value=https:gmail.com

$ grep -Po '(?<=url=).*(?= #)'  file
http://google.com

--edit---

I just seen that you edited your input sample Smilie

Code:
$ grep 'http' file | grep -v '^#'

Last edited by Akshay Hegde; 02-24-2014 at 02:03 PM..
# 7  
Old 02-24-2014
Code:
grep -v "^#" file

Last edited by Franklin52; 02-24-2014 at 02:33 PM.. Reason: Please use code tags, thanks
 
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