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[Solved] Variable defined in .bashrc not intializing in script

 
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# 1  
Old 02-12-2014
[Solved] Variable defined in .bashrc not intializing in script
I have the variable defined in .bashrc

BIN_DIR="/usr/local/dw"

and in my shell script i am using below.

Code:
#!/bin/bash
echo "Bin Dir: ${BIN_DIR}"
. "${BIN_DIR}"/dwh_Loadfuncs.sh

Output:
Code:
Bin Dir:
/usr/local/dw/dwh_LoadXMLFileIntoStage.sh: line 7: /dwh_Loadfuncs.sh: No such file or directory
/dwh_Loadfuncs.sh

May i please know why variable $BIN_DIR is not initialized?

Thank you.

---------- Post updated at 02:22 PM ---------- Previous update was at 02:20 PM ----------

Quote:
Originally Posted by Ariean
I have the variable defined in .bashrc

BIN_DIR="/usr/local/dw"

and in my shell script i am using below.

Code:
#!/bin/bash
echo "Bin Dir: ${BIN_DIR}"
. "${BIN_DIR}"/dwh_Loadfuncs.sh

Output:
Code:
Bin Dir:
/usr/local/dw/dwh_LoadXMLFileIntoStage.sh: line 7: /dwh_Loadfuncs.sh: No such file or directory
/dwh_Loadfuncs.sh

May i please know why variable $BIN_DIR is not initialized?

Thank you.
never mind i got the answer thank you.
# 2  
Old 02-12-2014
I presume it's because the variable hadn't been exported? It's helpful if you tell us how you solved your problem.
# 3  
Old 02-12-2014
Quote:
Originally Posted by Scott
I presume it's because the variable hadn't been exported? It's helpful if you tell us how you solved your problem.
I put a line to source .bashrc file.
HTML Code:
#!/bin/bash
. ~/.bashrc
echo "Bin Dir: ${BIN_DIR}"
. "${BIN_DIR}"/dwh_Loadfuncs.sh
# 4  
Old 02-13-2014
You wouldn't need to source the .bashrc if the variable had been exported.
 
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