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How to check if a number exists?

 
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# 1  
Old 12-03-2013
How to check if a number exists?
Hello,
May i please know how do i check if the given input argument is one of the listed numbers then success else failure. I am using bash shell.

Code:
if [ $1 is one of these (1,12,21,32....) ]
then
     echo "success"
else
     echo "failure"
fi

Thank you.
# 2  
Old 12-03-2013
This kind of problem seems better suited to a case-statement.

i.e.
Code:
case "$1" in
  12|122|21|32) echo Eureka!;;
  *?) echo No show
esac

This User Gave Thanks to Scott For This Post:
Ariean
# 3  
Old 12-03-2013
Use case statement to check one variable for different values
Code:
case $1 in
1|12|21|32)
  echo "success"
;;
*)
  echo "failure"
;;
esac

Most shells allow symmetric parentheses
Code:
(1|12|21|32)

to satisfy the editor's syntax highlighting.
This User Gave Thanks to MadeInGermany For This Post:
Ariean
 
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