UNIX for Dummies Questions & Answers

Hello ( sorry newbie question )
I don't understand something im trying to make simple alias that takes 1 arg but it don't gives me the desire result
here is what I have :
stlist | awk '{print "ls -l "$2}'
now I want to translate it to alias that takes instead of the $2 one arg
so I did :
alias stlistdir "stlist | awk '{print "ls -l "\!*}'"
also tried:
alias stlistdir "stlist | awk '{print "ls-l $"\!*}'"

but didn't get the desire results, im getting only the print of the second column when I type : stylistic 2

stlistdir without the ls -l , why ?

It is simple, you only see the command in standard output because you are just printing in awk and you not executing the command.

Could you post the output of stlist command, you want to do ls -lrt to the output of 2nd column of stlist command ?

well this is the thing I don't what it to execute the ls-l command, only to print it
so the output will be when I run the alias stlist 2 for instance:
ls -l file1
ls -l file2
ls -l file3

alias stlistdir "stlist | awk '{print "ls -l "\!*}'"

If you see the above statment, you are using double quotes in two places, one for alias and one for awk.... it obviously mismatch...

try this in ksh

alias stlistdir ="stlist | sed 's/^/ls -l /g'"

The following statement also not working as well..

stlist | awk '{print "ls -l "$2}'

there should be a "," before $2.

I guess I didn't explain my self very well
what I need simply is transform this one liner
stlist | awk '{print "ls -l "$2}'
where stlist is simple program that gives me list of files from repository
and from the output of this stlist command I want to take the second column ( this is the file name )
and add the "ls -l" command, now in the alias I want to make the $2 part as argument
that is sometime the user will get the second column or third depends on the number he typed in the alias
I hope I made my self clear now
thanks