Subtracting A month from an arbitrary date in UNIX


 
Thread Tools Search this Thread
Top Forums UNIX for Dummies Questions & Answers Subtracting A month from an arbitrary date in UNIX
# 8  
Old 10-10-2013
cygwin uses the bash shell. Your putty connection is not to cygwin, it is to another UNIX box. On that system your user account is set up to use the ksh shell.
 
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. UNIX for Beginners Questions & Answers

Changing CSV files with date . Subtracting date by values

Hi All, I have a CSV file which is as below. Basically I need to take the year column in it and find if the year is >= 20152 . If that is then I should subtract all values by 6. In the below example in description I am having number mentioned as YYWW so I need to subtract those by -5. Whereever... (8 Replies)
Discussion started by: arunkumar_mca
8 Replies

2. Shell Programming and Scripting

Subtracting months from passed Date

Hi All, I am getting a date from environment variable and want to do some processing by subtracting 2 months from the date passed through the environment variable. I am trying the following syntax : date_var=2014-08-31 date_2M_ago='$date_var+"%d%m%y" --$date_var="2 months ago" '... (3 Replies)
Discussion started by: Rahul Raj
3 Replies

3. Shell Programming and Scripting

Adding/ Subtracting from Date

Hi , How can I add/substruct x number of days with date? For example My_Date=`date` Now I need Hope it's clear. (2 Replies)
Discussion started by: Anupam_Halder
2 Replies

4. Shell Programming and Scripting

Help with getting last date of previous month and first date of previous 4th month from current date

I have requirment to get last date of previous month and the first date of previous 4th month: Example: Current date: 20130320 (yyyymmdd) Last date of previous month: 20130228 (yyyymmdd) First date of previous 4th month: 20121101 (yyyymmdd) In my shell --date, -d, -v switches are not... (3 Replies)
Discussion started by: machomaddy
3 Replies

5. Shell Programming and Scripting

SQL one liner for subtracting 1 from date

I got a statement like below to subtract 1 from given date using teradata. I am looking for a one line unix command to perform the same. select 'parse_this_record', (DATE '${FILE_DATE}' - 1) (FORMAT 'YYYY-MM-DD'); Input: 2012-02-21 Expected Output: 2012-02-20 PS: One liner because I am... (2 Replies)
Discussion started by: siteregsam
2 Replies

6. UNIX for Dummies Questions & Answers

print previous month (current month minus 1) with Solaris date and ksh

Hi folks month=`date +%m`gives current month Howto print previous month (current month minus 1) with Solaris date and ksh (7 Replies)
Discussion started by: slashdotweenie
7 Replies

7. UNIX for Dummies Questions & Answers

adding or subtracting days in the o/p of date

how can we add or subtract days from the output of date command in unix... like if i want to subtract a day from the result of date command like this.. v_date=`date +%Y%m%d` this wud give me 20080519 now i want to subtract one day from this.. so tht it wud give me 20080518.. how do i do... (1 Reply)
Discussion started by: St.Fartatric
1 Replies

8. UNIX for Dummies Questions & Answers

How do I set my date in a unix script to 'new month

Hi, I'm a newbie to unix and i'm loving every bit of it. I need assistance in setting my date function in my script to "new month". What I want to do is define the "newmonth" as the 1st of every month so my script can run by this time evry month through the year. Can someone assist. ... (1 Reply)
Discussion started by: Agent704
1 Replies

9. Shell Programming and Scripting

Subtracting date / timestamps

I have looked through the forums and found many date / time manipulation tools, but cannot seem to find something that fits my needs for the following. I have a log file with date time stamps like this: Jun 21 17:21:52 Jun 21 17:24:56 Jun 21 17:27:59 Jun 21 17:31:03 Jun 21 17:34:07 Jun... (0 Replies)
Discussion started by: roadcyclist
0 Replies

10. Shell Programming and Scripting

how to get month last date in unix

Hello I want to get end date of the any month in unix . is there any function to do this. we can get month from date command 'date +%b' example: If Feb month then last date is 28 if sep then last date 30. like this thanks please help (12 Replies)
Discussion started by: rajan_ka1
12 Replies
Login or Register to Ask a Question
DATETIME.SETISODATE(3)							 1						    DATETIME.SETISODATE(3)

DateTime::setISODate - Sets the ISO date

       Object oriented style

SYNOPSIS
public DateTime DateTime::setISODate (int $year, int $week, [int $day = 1]) DESCRIPTION
Procedural style DateTime date_isodate_set (DateTime $object, int $year, int $week, [int $day = 1]) Set a date according to the ISO 8601 standard - using weeks and day offsets rather than specific dates. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $year - Year of the date. o $week - Week of the date. o $day - Offset from the first day of the week. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.setISODate(3) example Object oriented style <?php $date = new DateTime(); $date->setISODate(2008, 2); echo $date->format('Y-m-d') . " "; $date->setISODate(2008, 2, 7); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create(); date_isodate_set($date, 2008, 2); echo date_format($date, 'Y-m-d') . " "; date_isodate_set($date, 2008, 2, 7); echo date_format($date, 'Y-m-d') . " "; ?> The above examples will output: 2008-01-07 2008-01-13 Example #2 Values exceeding ranges are added to their parent values <?php $date = new DateTime(); $date->setISODate(2008, 2, 7); echo $date->format('Y-m-d') . " "; $date->setISODate(2008, 2, 8); echo $date->format('Y-m-d') . " "; $date->setISODate(2008, 53, 7); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2008-01-13 2008-01-14 2009-01-04 Example #3 Finding the month a week is in <?php $date = new DateTime(); $date->setISODate(2008, 14); echo $date->format('n'); ?> The above examples will output: 3 SEE ALSO
DateTime.setDate(3), DateTime.setTime(3). PHP Documentation Group DATETIME.SETISODATE(3)