Quick UNIX command to display specific lines in the middle of a file from/to specific word


 
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# 1  
Quick UNIX command to display specific lines in the middle of a file from/to specific word

This could be a really dummy question.

I have a log text file.

What unix command to extract line from specific string to another specific string.

Is it something similar to?:

more +/"string" file_name


Thanks
# 2  
Hello,

your requirement is not clear but still one example is as follows.
Let me know your exact requirement so that we can find out exact way.
Here is an example for same.


let us say a file named check_data_column.

Code:
$ cat check_data_column
1 2 3 4
5 6 7 8
9 10 11 12
$

And we have requirement to fgrep the data between digit 1 to digit 8.
Here is the command to find out text that starts from 1 and ends with 8,
just an example.

Code:
$ awk '/^1/,/8$/' check_data_column



Output wil be as follows.

Code:
1 2 3 4
5 6 7 8




Thanks,
R. Singh
# 3  
Hello,
bellow expanded description of my problem:

I've following text file:

Code:
2013/08/12 10:00 nondisplayed Text
2013/08/12 10:00 nondisplayed Text
2013/08/12 10:00 nondisplayed Text
2013/08/12 10:00 nondisplayed Text
2013/08/12 10:00 nondisplayed Text
2013/08/12 10:00 nondisplayed Text
2013/08/12 10:00 Text 1
Text 2: something
2013/08/12 10:00 Text 2
Text 3: something
Text 3: something
Text 3: something
Text 3: something
Text 3: something
End of displayed text.
2013/08/12 10:00 nondisplayed Text
2013/08/12 10:00 nondisplayed Text
2013/08/12 10:00 nondisplayed Text

I need to extract all lines from "Text 1" to "End of displayed text.".

On the output I would get:

Code:
Text 1
Text 2: something
2013/08/12 10:00 Text 2
Text 3: something
Text 3: something
Text 3: something
Text 3: something
Text 3: something
End of displayed text.



Thank you for your help.
Regards, AT.
# 4  
Code:
awk '/Text 1/,/End of displayed text/' filename

# 5  
It works! Smilie. Thanks for your help. Regards, AT.
 

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