how to strip out the contents of file using grep


 
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# 8  
Old 11-22-2005
sed -e 's/^isa//g' -e 's/[89][469][279]$//g' td.txt

this takes out the isa from beginning and then the numbers (three numbers) from the end of the line.you may output this code to a new file once you satisfied with the result.
# 9  
Old 11-22-2005
Hi Rkl1,

Thanks for the reply!!!

This command just shows all the contents of the file. There are multiple ISA in the file, so it is showing all of them. But, I just want to see the contents for 999 not for 862 or others.

In other words, what I need is look for the occurences of the 997 in the file. Once I find any 997, look for ISA before the 997 and then look for ISA after the 997 and extract that pice of data. i.e. extract the data between two ISA's which has 997 and there can be multiple occurences of 997 in a file.

Regards,
Inder
# 10  
Old 11-22-2005
using gawk:
Code:
gawk -v RS='ISA' '/997/ {print RS $0}' myFile.txt

# 11  
Old 11-22-2005
Thanks a lot sir!!

It works perfect. Let me do some more testing with adding some other data to the file and I will let you know the results. Thanks!!!

Inder
# 12  
Old 11-28-2005
Hi Vgersh99,

Sorry for the delayed response.

It works perfectly. Thanks for all your help.

Regards,
Inder
 
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