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Awk- catching the last two chars

 
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# 8  
Old 11-21-2005
Quote:
Originally Posted by rkl1
since I dont have much experience in any thing: I will do this work in a simple but long way: so laughing is allowed looking at my code.

for file in `cat t40.txt|nawk '{print $3}'`;do
n=`echo $file|wc -C`
n=`expr $n - 1`
n1=`expr $n - 1`
echo $file|cut -c $n1-$n

I dont know why wc -C brings one more number than the real number of characters are there.

echo "this"|wc -C

this gives value 5 instead of 4.

thanks.

Have you tried running this code?
# 9  
Old 11-21-2005
I forgot to include the syntax done at the end of the script.

thanks.
# 10  
Old 11-22-2005
awk last characters
Thanks, I tried both the:...

nawk '{print substr($0, length($0)-1)}' text.file

and also the

sed 's/^.*\(..\)$/\1/' text.file

and both these work

rkL1 ---thanks for your input, but these simpler methods works fine...

thanks to all for your speedy responses'
 
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