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How do I pull the value between curly braces?


 
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# 1  
Old 07-03-2013
How do I pull the value between curly braces?

Hi everyone,

I've got a file that looks like this:
Code:
uid{508}pid{22224}pname{/PPROGRAM/pprgramx -profile:LIVE -serv:as ...

I want to pull the value of pid between the curly braces, or 22224 in this example. pid is always the second pair of curly braces, but the length of the number is variable.

So far I have:
Code:
awk '$1 ~/pid/{ print $0 }' file1

But that pulls the whole line.

Thank you!
# 2  
Old 07-03-2013
Code:
awk -F"[{}]" '/pid/ { print $4 }' inputfile

# 3  
Old 07-03-2013
That worked nicely. But how does the $4 in the last argument pull the correct value? I thought awk needed spaces between fields. Thank you!
# 4  
Old 07-03-2013
Or:
Code:
awk '$1=="pid"{print $2}' FS=\{ RS=\} file

# 5  
Old 07-04-2013
With Sed.
Code:
sed 's/.*pid{\([^}]*\).*/\1/' infile

# 6  
Old 07-04-2013
The FS or Field Separator that Corona688 has included tells awk what to use instead of white space.



Robin
# 7  
Old 07-05-2013
Thanks for all the replies and different solutions.
 

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