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How to grep with certain condition?

 
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# 1  
Old 05-17-2013
How to grep with certain condition?
hi all,
i have an xml what i have to do is to search for the source id(s1) and if it matches with that in xml then extract the file mask from the name of the file i.e if the file name is
idr_%YYYY%%MM%%DD%_%N%.idr then , i want the part after first %
and before last % ie in this case
%YYYY%%MM%%DD%_%N%


Code:
<?xml version="1.0" encoding="UTF-8"?>
<Sources>
  <DatabaseConnection>
    <TNSName>dgid1rr</TNSName>
    <Username>rte</Username>
    <Password>rted1</Password>
  </DatabaseConnection>
  <Logger>
    <LogFilePath>/export/home/dgid1rr/merge/log</LogFilePath>
    <LogFileName>idr_merge_log</LogFileName>
    <LogLevel>Info</LogLevel>
  </Logger>
  <Source id="S1">
    <FileMask>idr_%YYYY%%MM%%DD%_%N%.idr</FileMask>
    <TimeLag>100</TimeLag>
    <Backup>True</Backup>
    <InputFilePath>/export/home/dgid1rr/cdr1/input</InputFilePath>
    <OutputFilePath>/export/home/dgid1rr/merge/cdr1/output</OutputFilePath>
    <BackupFilePath>/export/home/dgid1rr/merge/cdr1/backup</BackupFilePath>
    <ProcessOrder>FileTimestamp</ProcessOrder>
    <Enable>True</Enable>
    <MaxFiles>3</MaxFiles>
    <MaxRecs>25</MaxRecs>
  </Source>
  <Source id="S2">
    <FileMask>idr_%2N%.idr</FileMask>
    <TimeLag>300</TimeLag>
    <Backup>True</Backup>
    <InputFilePath>/export/home/dgid1rr/merge/cdr2/input</InputFilePath>
    <OutputFilePath>/export/home/dgid1rr/merge/cdr2/output</OutputFilePath>
    <BackupFilePath>/export/home/dgid1rr/merge/cdr2/backup</BackupFilePath>
    <ProcessOrder>OSTimestamp</ProcessOrder>
    <Enable>True</Enable>
    <MaxFiles>2</MaxFiles>
  </Source>
</Sources>

Thanks
Last edited by Scott; 05-17-2013 at 04:58 PM.. Reason: Moved thread - Not a Redhat question
# 2  
Old 05-17-2013
Code:
awk -F'[<>]' '/Source id="S1"/{getline;sub(/[a-z_]*%/,"%",$3);sub(/%\..*/,"%",$3);print $3}' xmlfile
%YYYY%%MM%%DD%_%N%

# 3  
Old 05-17-2013
what should i do if my file mask is after three lines of source id ie something like this


Code:
<Source id="S1">
    <Type>Ericsson3GSGSN</Type>
    <Operator>0</Operator>
    <Version>1.0</Version> 
    <FileMask>idr_%YYYY%%MM%%DD%_%N%.idr</FileMask>

Last edited by Scott; 05-19-2013 at 12:56 PM.. Reason: icode -> code tags
# 4  
Old 05-17-2013
Then call getline 4 times:
Code:
awk -F'[<>]' '/Source id="S1"/{getline;getline;getline;getline;sub(/[a-z_]*%/,"%",$3);sub(/%\..*/,"%",$3);print $3}' xmlfile

---------- Post updated at 15:40 ---------- Previous update was at 15:38 ----------

Forget getline, here is a much better approach:
Code:
awk -F'[<>]' '/Source id="S1"/{f=1}f&&/<FileMask>/{sub(/[a-z_]*%/,"%",$3);sub(/%\..*/,"%",$3);print $3;exit}' xmlfile

This User Gave Thanks to Yoda For This Post:
ramsavi
# 5  
Old 05-18-2013
hi, i used the same code when the value of source id = value stored in some array but then it is not giving the result . the code which i used is like this

Code:
#!/bin/bash -xv

val_1=$( sqlplus -s rte/rted2@rel76d2 << EOF
set heading off
select max(istat_id) from cvt_istats;
exit
EOF
)
echo "val_1: $val_1"

nohup ./cvt -f MediationSources.xml &
sleep 60

declare -a arr
arr=($( sqlplus -s rte/rted2@rel76d2 << EOF
set heading off
select source_id from cvt_istats where istat_id > $val_1;
exit
EOF
))
echo "val_2: $arr"

i=0
len=${#arr[@]}
echo $len

while [ $len -gt $i ]
do
  value= cat MediationSources.xml |awk -F'[<>]' '/Source id="${arr[$i]}"/{f=1}f&&/<FileMask>/{sub(/[a-z_]*%/,"%",$3);sub(/%\..*/,"%",$3);print $3;exit}'
  echo "$value file mask pass "
  i=$(( $i + 1 ))
done
~
~

can you please check wher i am going wrong
Last edited by vgersh99; 05-18-2013 at 09:53 AM.. Reason: fixed code tags
# 6  
Old 05-18-2013
It should be:
Code:
value=$( awk -F'[<>]' '/Source id="${arr[$i]}"/{f=1}f&&/<FileMask>/{sub(/[a-z_]*%/,"%",$3);sub(/%\..*/,"%",$3);print $3;exit}' MediationSources.xml )

 
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