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Remove duplicates from a file

 
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# 8  
Old 05-09-2013
Thanks Vidyadhar,this is working fine. I m getting the specified data but the order is getting changed. The data that i m getting here is -
Code:
104       MNO       17/04/1984      12000
107       XYZ       24/09/1978      6000
101       ABC       11/01/1991      5000
102       DEF       15/04/1998      8000

But what i am expecting is -
Code:
101       ABC       11/01/1991      5000
104       MNO       17/04/1984      12000
102       DEF       15/04/1998      8000
107       XYZ       24/09/1978      6000

Is there any way in which we can get the result without changing their order?
Last edited by radoulov; 05-09-2013 at 06:14 AM..
# 9  
Old 05-09-2013
Code:
awk '!X[$0]++' file

# 10  
Old 05-09-2013
Quote:
Originally Posted by saga20
But sort -u will show the original records.As per my sample data as posted above,it ll get only 2 records that r unique. But i want just duplicated to be removed. So that it ll get 4 records.
No. The command:
Code:
sort -ur -o Emp.txt Emp.txt

When Emp.txt contains:
Code:
Empid Empname Joining_Date Salary
101 ABC 11/01/1991 5000
104 MNO 17/04/1984 12000
102 DEF 15/04/1998 8000
101 ABC 11/01/1991 5000
107 XYZ 24/09/1978 6000
104 MNO 17/04/1984 12000
101 ABC 11/01/1991 5000

replaces the contents of Emp.txt with:
Code:
Empid Empname Joining_Date Salary
107 XYZ 24/09/1978 6000
104 MNO 17/04/1984 12000
102 DEF 15/04/1998 8000
101 ABC 11/01/1991 5000

I used reverse sort order to keep the header at the start of file. If it is important to keep the output in the same (unsorted) order as the input, you could try:
Code:
awk '! ($0 in o) {o[$0];print}' Emp.txt > Emp$$.txt && mv Emp$$.txt Emp.txt

# 11  
Old 05-09-2013
As a side note, the latest GNU awk (Awk 4.1.0 beta) supports in-place editing.
The code would be:
Code:
awk -i inplace '!seen[$0]++' Emp.txt

# 12  
Old 05-09-2013
Quote:
Originally Posted by pamu
Code:
awk '!X[$0]++' file

Thanks Pamu,its working fine as per my requirement... Smilie

---------- Post updated at 02:58 PM ---------- Previous update was at 02:54 PM ----------

Quote:
Originally Posted by Don Cragun
No. The command:
Code:
sort -ur -o Emp.txt Emp.txt

When Emp.txt contains:
Code:
Empid Empname Joining_Date Salary
101 ABC 11/01/1991 5000
104 MNO 17/04/1984 12000
102 DEF 15/04/1998 8000
101 ABC 11/01/1991 5000
107 XYZ 24/09/1978 6000
104 MNO 17/04/1984 12000
101 ABC 11/01/1991 5000

replaces the contents of Emp.txt with:
Code:
Empid Empname Joining_Date Salary
107 XYZ 24/09/1978 6000
104 MNO 17/04/1984 12000
102 DEF 15/04/1998 8000
101 ABC 11/01/1991 5000

I used reverse sort order to keep the header at the start of file. If it is important to keep the output in the same (unsorted) order as the input, you could try:
Code:
awk '! ($0 in o) {o[$0];print}' Emp.txt > Emp$$.txt && mv Emp$$.txt Emp.txt

Thanks Don Cragun for ur response,but after executing this,my file is becoming empty. Anyways i got the solution.

---------- Post updated at 02:59 PM ---------- Previous update was at 02:58 PM ----------

Quote:
Originally Posted by radoulov
As a side note, the latest GNU awk (Awk 4.1.0 beta) supports in-place editing.
The code would be:
Code:
awk -i inplace '!seen[$0]++' Emp.txt

Thanks Radoulov for ur response,but after executing this,my file is becoming empty. Anyways i got the solution.
 
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