UNIX for Dummies Questions & Answers

Hi All,

Can anyone please help me in sort out the command to get the following command

say File abc.log contains

....
......
This is the first line
This is the second line
This is the third line
This is the fourth line
This is the fifth line

This is the first line
This is the second line
This is the third line
This is the fourth line
This is the fifth line
........
..

..


output
=====
This is the first line
This is the fourth line

Output should be the first search occurence and the second occurence only . But when i trued i was getting the lines all between the first occurence and second search occurece.


Hoping any one of can help me out


thanks
Satish

I'm sorry I don't understand the question, you speak about first and second occurrences, but this does not seem to correspond with the required output.

Below is the sample file:

","200USD",11,"1e58d7d167c35"
"1e0f117d167c35",12,"<BasicPage>
<DateOfBirth>08/03/1982</DateOfBirth>
<dasda>
<dasdfaf>
<AddressGroup>
<AddressLine1></AddressLine1>
<AddressCity></AddressCity>
<AddressState></AddressState>
......


output :
=======

200USD ( This is in the first line)
<DateOfBirth>08/03/1982</DateOfBirth> ( this is in the inbetween xml)


Thanks
Satish

Looks like you want all the lines between the tags BasicPage and DateOfBirth

Try this.

Code:

sed -n -e '/BasicPage/p' -e '/DateOfBirth/p' input.txt

thanks for quick replying.

I want only the lines of tags BasicPage and DateOfBirth.

anyone Please help me in sorting of this command

thanks
Satish

please do not post client-specific data online ... you might want to edit your post to remove the data unless you prefer to run into issues with client confidentiality laws ...

Only the data between the tags or the lines containing the tags as well ?

For the latter, did you try the sed command provided ?

Edit. Just like JustIce said, modify your post to remove the client info. Unless it is a generated info.