UNIX for Dummies Questions & Answers

Code:

mon_yy=${1}
date_found=`find_end_day $mon_yy`
export_dealer_changes ${date_found}

Hello
I am trying to pull a formatted date back from the function find_end_day and pass it into the function export_dealer_changes. When I try the above the variable date_found is empty. I have tried various different syntax and it still doesn't work, please can anyone advise what I am doing wrong. If I run either function separately they work, it is the passing of the result from one to the other that I can not get to work.

Many thanks

Myf

Without knowing the value contained in $1 and the code that comprises find_end_day and export_dealer_changes and the shell you're using and the system on which you're running this code, there isn't much we can do to help other than to point out that whenever dealing with user-supplied data you should be prepared to have field separators in that data (i.e., you need to quote strings that might contain whitespace characters).

Code:

mon_yy=${1}
date_found=$(find_end_day "$mon_yy")
export_dealer_changes "$date_found"

I understand that normally you are looking to find out what the code does to respond, but what I am trying to find out is if it is possible to get the result of any function returned into a variable and then that variable passed into another function.

The value returned by a function can be stored.
A function can call a function.
The value returned by a function that has been captured in a variable can be passed to a function.
An argument to a function can be the return value from another function.

If you want us to explain why your code isn't doing one of the above, you have to show us your code!