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How can I match . (actual dot) using sed?

 
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# 1  
Old 09-19-2005
How can I match . (actual dot) using sed?
Hi All,
How can I match . (actual dot) using sed? Please help.

Thanks
# 2  
Old 09-19-2005
You need to escape it with a \

Look at this.

Code:
sh-2.05b$ cat jing.txt
test
.
test.match

Code:
sh-2.05b$ sed -n -e '/\./p' jing.txt
.
test.match

# 3  
Old 09-19-2005
Thanks vino.

But this doesn't work. I am looking for /./* (one or more of /./ and replace with a single /./

I tried dereferencing . and /
it doen't work. Please help.

Thanks
# 4  
Old 09-19-2005
This is going to be a confusing regex.

Code:
sed -e 's#\/\.\/\{1,\}#\/\.\/#g'

vino
# 5  
Old 09-19-2005
Please see below:

cat 1 gives:

Code:
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

Code:
sed -e 's#\.\{1,\}#\.#g' 1 > 2

now see cat 2

Code:
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

It is not working.
Last edited by rbatte1; 01-13-2017 at 07:17 AM.. Reason: Added CODE tags
# 6  
Old 09-19-2005
Yes the previous solution will not work.

But this should work

Code:
sh-2.05b$ cat jing.txt 
test
/./
test/.//.//./match
sh-2.05b$ sed  -e 's#\(\/\.\/\)*#\1#g' jing.txt 
test
/./
test/./match

vino
# 7  
Old 09-19-2005
Code:
cat 1
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

Code:
sed  -e 's#\(\/\.\/\)*#\1#g' 1 > 2

Code:
cat 2
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

It is not working. Is there is special reason why this doesn't work?
Last edited by rbatte1; 01-13-2017 at 07:17 AM.. Reason: Added CODE tags
 
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