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Regular expression help

 
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Old 01-18-2013
Your regular expression matches: zero or more occurrences of [0-9] followed by a literal dot ., followed by zero or more occurrences of [0-9].
The == / != operators in ksh don't support regular expressions, but only shell pattern matching.
As I already said, check if your ksh version supports the =~ operator (but I doubt, if it's really an x88 implementation).
You should also modify the pattern (if used as a regular expression) to restrict the matching (see the examples in the previous two posts).

If your shell doesn't support regular expressions, use grep, as balajesuri suggested (you may need to use > /dev/null
instead of -q with some grep implementations.
 
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LEARN ABOUT SUSE

ausearch_add_regex

AUSEARCH_ADD_REGEX(3)						  Linux Audit API					     AUSEARCH_ADD_REGEX(3)

NAME

       ausearch_add_regex - use regular expression search rule

SYNOPSIS

       #include <auparse.h>

       int ausearch_add_regex(auparse_state_t *au, const char *expr);

DESCRIPTION

       ausearch_add_regex  adds  one  search condition based on a regular expression to the current audit search expression. The search conditions
       can then be used to scan logs, files, or buffers for something of interest. The regular	expression  follows  the  posix  extended  regular
       expression conventions, and is matched against the full record (without interpreting field values).

       If an existing search expression E is already defined, this function replaces it by (E && this_regexp).

RETURN VALUE

       Returns -1 if an error occurs; otherwise, 0 for success.

SEE ALSO

       ausearch_add_expression(3), ausearch_add_item(3), ausearch_clear(3), ausearch_next_event(3), regcomp(3).

AUTHOR

       Steve Grubb

Red Hat 							     Sept 2007						     AUSEARCH_ADD_REGEX(3)